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PT is a tangent to the circle TYZX. YT = YX and PT is a tangent to the circle TYZX. YT = YX and o. Calculate A. 50o B. 65o C. 85o D. 130o Correct Answer: Option B Explanation XTY = 50o = TXY = (frac{130^o}{2}) = 65o `, props: [‘comment’], data() { return {} }, methods: {} }) {{ reply.posted_by.display_name }}:   {{ reply.created_at }} `, props: [‘comment’, ‘reply’, ‘rate_selection’, ‘token’], data() { return {} }, methods: {} })

PT is a tangent to the circle TYZX. YT = YX and o. Calculate A. 50o B. 65o…
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In the diagram, PTS is a tangent to the circle TQR at T. Calculate In the diagram, PTS is a tangent to the circle TQR at T. Calculate A. 120o B. 70o C. 60o D. 40o Correct Answer: Option B Explanation RTS = RQT (angle between a tangent and a chord at the point of contact is equal to the angle in the alternate segment) But R = Q + T = 180 RQT = 180o – (50 + 60) = 180o – 110o = 70o Since RQT = RTS = 70o `, props: [‘comment’], data() { return {} }, methods: {} }) {{ reply.posted_by.display_name }}:   {{ reply.created_at }} `, props: [‘comment’, ‘reply’, ‘rate_selection’, ‘token’], data() { return {} }, methods: {} })

In the diagram, PTS is a tangent to the circle TQR at T. Calculate A. 120o B. 70o…
Read More