In the diagram, TS is a tangent to the circle at S. |PR| and In the diagram, TS is a tangent to the circle at S. |PR| and o. Calculate A. 54o B. 44o C. 34o D. 27o Correct Answer: Option A Explanation In the diagram above, x1 = 180o – 117o = 63o(opposite angles of a cyclic quad.) x1 = x2 (base angles of isos. (Delta)) x1 + x2 + (alpha) = 180o (sum of angles of a (Delta) 63o + 63o + (alpha) = 180o (alpha) = 180o – (63 + 63)o = 54o `, props: [‘comment’], data() { return {} }, methods: {} }) {{ reply.posted_by.display_name }}:   {{ reply.created_at }} `, props: [‘comment’, ‘reply’, ‘rate_selection’, ‘token’], data() { return {} }, methods: {} })

In the diagram, TS is a tangent to the circle at S. |PR| and o. Calculate A. 54o…
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In the diagram, PR||SV||WY|, TX||QY|, In the diagram, PR||SV||WY|, TX||QY|, o and o.Find A. 120o B. 108o C. 72o D. 60o Correct Answer: Option C Explanation In the diagram, o(corresp. angles)o (alternate angles) o + 48o = 180o(sum of angles of a (Delta))o – 108o = 72o `, props: [‘comment’], data() { return {} }, methods: {} }) {{ reply.posted_by.display_name }}:   {{ reply.created_at }} `, props: [‘comment’, ‘reply’, ‘rate_selection’, ‘token’], data() { return {} }, methods: {} })

In the diagram, PR||SV||WY|, TX||QY|, o and o.Find A. 120o B. 108o C. 72o D. 60o Correct Answer:…
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