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In the diagram, (bar{PF}), (bar{QT}), (bar{RG}) intersect at S and PG||RG. If In the diagram, (bar{PF}), (bar{QT}), (bar{RG}) intersect at S and PG||RG. If o and A. 22o B. 45o C. 67o D. 89o Correct Answer: Option B Explanation In In the diagram given, (alpha) = 22o (vertically opp. angles), (alpha) = (beta) (alternate angles)o + (beta) = 180o (sum of angles of a (Delta)) o + 22o = 180oo – (133 + 22)o 45o `, props: [‘comment’], data() { return {} }, methods: {} }) {{ reply.posted_by.display_name }}:   {{ reply.created_at }} `, props: [‘comment’, ‘reply’, ‘rate_selection’, ‘token’], data() { return {} }, methods: {} })

In the diagram, (bar{PF}), (bar{QT}), (bar{RG}) intersect at S and PG||RG. If o and A. 22o B. 45o…
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In the diagram, O is the centre of the circle, In the diagram, O is the centre of the circle, o and o. Calculate the value of m. A. 30 B. 36 C. 40 D. 72 Correct Answer: Option A Explanation In the diagram above, (alpha) = 2mo (angle at centre = 2 x angle at circumference) (alpha) + 10mo = 360o (angle at circumference) (alpha) + 10mo = 360o(angles round a point) 2mo + 10mo = 360o 12mo = 360o mo = (frac{360^o}{12}) = 30o `, props: [‘comment’], data() { return {} }, methods: {} }) {{ reply.posted_by.display_name }}:   {{ reply.created_at }}

In the diagram, O is the centre of the circle, o and o. Calculate the value of m.…
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If cos (theta) = x and sin 60o = x + 0.5 0o If cos (theta) = x and sin 60o = x + 0.5 0oo, find, correct to the nearest degree, the value of (theta) A. 32o B. 40o C. 60o D. 69o Correct Answer: Option D Explanation sin 60o = x + 0.5 0o(given) 0.8660 = x + 0.5 0.8660 – 0.5 = x x = 0.3660 cos(theta) = x(given) cos(theta) = 0.3660 Hence, (theta) = cos-1(0.3660) = 68.53o = 69o (nearest degree) `, props: [‘comment’], data() { return {} }, methods: {} }) {{ reply.posted_by.display_name }}:   {{ reply.created_at }}

If cos (theta) = x and sin 60o = x + 0.5 0oo, find, correct to the nearest…
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